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Wednesday, October 13, 2010

hw #2-3 Sections 2-3 & 2-4

pg 64-65 #1-39 Multiples of 3   3,6,9,...
pg 68-69 #4-40 Multiples of 4   4,8,12,16...

We will be going over ALL homework for this unit on Friday, so BLOG me with questions or be ready to ask good questions on Friday!

4 comments:

  1. I can't get 32 on pg69

    i always get x=-3 but the check never works i am doing something wrong

    ReplyDelete
  2. OK, compare your steps with mine:

    when b=1/3

    (2 1/6) + x = -b
    (2 1/6) + x = -(1/3)... always use parens
    ask yourself... What's bothering x?
    2 1/6 is being added... so, subtract 2 1/6 from both sides
    x = -(1/3) - 2 1/6... now find a common denominator

    x = -(2/6) - 2 1/6

    Can you take it from here? Do you see your mistake yet?

    lmk... Mr. C.

    ReplyDelete
  3. Mr Chamberlain i was taking the pearson unit 2 review test and I got one wrong the problem was simplify -6 to the fourth power I got 1,296 but the computer said that it was wrong and the answer is -1,296 who is right?

    -paige

    ReplyDelete
  4. When you see a negative sign in front of a number or variable, you can treat it as a coefficient of -1. A coefficient is a multiplier.

    So, -6^4 is really -1*6^4.

    If you evaluate -1*6^4 you would perform the 6^4 first (yielding 1296) and then multiply by -1, yielding -1296. Fully "STRETCHED" it would look like this:
    (-1)(6)(6)(6)(6)

    Contrast that problem with (-6)^4. Since the negative sign is within the parens, if you STRETCH the problem to the fullest, you would get:
    (-1*6)(-1*6)(-1*6)(-1*6) which equals
    (-6)(-6)(-6)(-6) which equals +1296

    So the question is:
    Does -6^4=(-6)^4

    The answer is a resounding NO!

    ReplyDelete